Christopher Strevens

2013-04-20 14:05:16 UTC

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winding then the current sheet is 800 A so the plasma curent is 800 A.

The plasma is generated by the ionisation wire which is excited by 20KV

60KHz power supply.

The ion pressure is 800.800.mu/D/length of winding. But since the

current is actually a standing wave them there is a maximum current in

the middle and zero at the ends making the pressure a bit quite a bit

bigger near the middle. The pressure I calculated as about 10^8Pa and

the plasma heats by ohmic heating with the maximun near the middle and

near the axis. When the temperature reaches 6KeV (that is about 10^11 K

the power reaches its maximum. This is only near the middle and near the

axis the insulation is because the ionised gas does not diffuse outward

because of the ion pressuree and is kept near the maximum because it is

the maximum current. The fusion reactions futher heat the gas and the

ions exert pressure on the containment current this inducing more

current in the winding. The current density near the centre is very high

because the area over which it flowes is about 1mmx6mm so the current

density is 800/6E-6 or 8E8A/meter^2.

The copper loss is the resisance of the winding (2000Ohm) and the

current (40mA) which is 80 Watt.

The power generated is 0.5 Watt/cc/kPa^2 and with a reaction volume of

18E-2 so the power is 18E-2x0.5x(10E8/1000)^2 or 9E10Watt (90GW). It

cannot be run at that power because the current generated is too high

for the windings and since this extra current increasss the pressure the

power simply rises exponentially until the unit explodes.

THe power is controlled by the shunt regulator by shunting the windings

when the potential rises to the preset level.

To make a high power unit the reaction chamber remains the same but the

resonance winding is made of insulated copper tube of the same

inductance. This will have a smaller number of turns because the winding

has a bigger diameter. I do not know how to work the inductance out from

the number of turns and dimensions of the winding. You can estimate from

the gaussian formula for a single turn coil and after winding, measure

the inductance. Then calculate the capacitance for resonance at 50 Hz.

Calculate the potential reached at maximum power to estimate the voltage

rating of the capacitor and similarly the current rating. To get 50KW at

400 V the current output will be 125A. So the tank circuit must run at

about 1250A so only 10% is taken to load. The output winding will have

about 400T of 125A wire with the output voltage of 400 volt. To

calculate the potential across the tank circuit the turns of the

resonance winding need be known. So build the resonace cicuit first and

then find the potential it develops at low power (the exciter across the

resonance coil) and then measure work out the turns for the output

winding.

To reduce the copper loss and cool the winding the copper tube winding

needs liquid nitrogen flowing in the tube.

Dr Chris.

Dr Chris

http://www.cs003o327.webspace.virginmedia.com/